Integrand size = 25, antiderivative size = 86 \[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=-\frac {2^{\frac {5}{4}+m} a \sqrt {e \cos (c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{4}-m,\frac {5}{4},\frac {1}{2} (1-\sin (c+d x))\right ) (1+\sin (c+d x))^{\frac {3}{4}-m} (a+a \sin (c+d x))^{-1+m}}{d e} \]
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Time = 0.06 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {2768, 72, 71} \[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=-\frac {a 2^{m+\frac {5}{4}} \sqrt {e \cos (c+d x)} (\sin (c+d x)+1)^{\frac {3}{4}-m} (a \sin (c+d x)+a)^{m-1} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{4}-m,\frac {5}{4},\frac {1}{2} (1-\sin (c+d x))\right )}{d e} \]
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Rule 71
Rule 72
Rule 2768
Rubi steps \begin{align*} \text {integral}& = \frac {\left (a^2 \sqrt {e \cos (c+d x)}\right ) \text {Subst}\left (\int \frac {(a+a x)^{-\frac {3}{4}+m}}{(a-a x)^{3/4}} \, dx,x,\sin (c+d x)\right )}{d e \sqrt [4]{a-a \sin (c+d x)} \sqrt [4]{a+a \sin (c+d x)}} \\ & = \frac {\left (2^{-\frac {3}{4}+m} a^2 \sqrt {e \cos (c+d x)} (a+a \sin (c+d x))^{-1+m} \left (\frac {a+a \sin (c+d x)}{a}\right )^{\frac {3}{4}-m}\right ) \text {Subst}\left (\int \frac {\left (\frac {1}{2}+\frac {x}{2}\right )^{-\frac {3}{4}+m}}{(a-a x)^{3/4}} \, dx,x,\sin (c+d x)\right )}{d e \sqrt [4]{a-a \sin (c+d x)}} \\ & = -\frac {2^{\frac {5}{4}+m} a \sqrt {e \cos (c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{4}-m,\frac {5}{4},\frac {1}{2} (1-\sin (c+d x))\right ) (1+\sin (c+d x))^{\frac {3}{4}-m} (a+a \sin (c+d x))^{-1+m}}{d e} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.97 \[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=-\frac {2^{\frac {5}{4}+m} \sqrt {e \cos (c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{4}-m,\frac {5}{4},\frac {1}{2} (1-\sin (c+d x))\right ) (1+\sin (c+d x))^{-\frac {1}{4}-m} (a (1+\sin (c+d x)))^m}{d e} \]
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\[\int \frac {\left (a +a \sin \left (d x +c \right )\right )^{m}}{\sqrt {e \cos \left (d x +c \right )}}d x\]
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\[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=\int { \frac {{\left (a \sin \left (d x + c\right ) + a\right )}^{m}}{\sqrt {e \cos \left (d x + c\right )}} \,d x } \]
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\[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=\int \frac {\left (a \left (\sin {\left (c + d x \right )} + 1\right )\right )^{m}}{\sqrt {e \cos {\left (c + d x \right )}}}\, dx \]
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\[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=\int { \frac {{\left (a \sin \left (d x + c\right ) + a\right )}^{m}}{\sqrt {e \cos \left (d x + c\right )}} \,d x } \]
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\[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=\int { \frac {{\left (a \sin \left (d x + c\right ) + a\right )}^{m}}{\sqrt {e \cos \left (d x + c\right )}} \,d x } \]
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Timed out. \[ \int \frac {(a+a \sin (c+d x))^m}{\sqrt {e \cos (c+d x)}} \, dx=\int \frac {{\left (a+a\,\sin \left (c+d\,x\right )\right )}^m}{\sqrt {e\,\cos \left (c+d\,x\right )}} \,d x \]
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